TO FIND WHETHER A NO. IS ARMSTRONG OR NOT IN C++
   /* FOR EX. 153 = (1*1*1)+(5*5*5)+(3*3*3) */     # include <iostream.h>  # include <conio.h>   void main ()  {        clrscr();        int a,sum=0;        long int n,num;        cout<<"Enter the no. : ";        cin>>n;        num = n;        for(;n>0;)          {               a=n%10               sum=sum+(a*a*a);               n=n/10;          }        if(sum==num)           {                 ...