TO FIND WHETHER A NO. IS ARMSTRONG OR NOT IN C++

/* FOR EX. 153 = (1*1*1)+(5*5*5)+(3*3*3) */

 

# include <iostream.h>

# include <conio.h>

void main ()

{

      clrscr();

      int a,sum=0;

      long int n,num;

      cout<<"Enter the no. : ";

      cin>>n;

      num = n;

      for(;n>0;)

        {

             a=n%10

             sum=sum+(a*a*a);

             n=n/10;

        }

      if(sum==num)

         {

                     cout<<"IT IS AN ARMSTRONG NUMBER...";

         }

     else

        {

                     cout<<"IT IS NOT AN ARMSTRONG NUMBER...";

        }

     getch();

}