TO FIND WHETHER A NO. IS ARMSTRONG OR NOT IN C++
/* FOR EX. 153 = (1*1*1)+(5*5*5)+(3*3*3) */ # include <iostream.h> # include <conio.h> void main () { clrscr(); int a,sum=0; long int n,num; cout<<"Enter the no. : "; cin>>n; num = n; for(;n>0;) { a=n%10 sum=sum+(a*a*a); n=n/10; } if(sum==num) { ...